1.

What will be the freezing point `("in"^(@)C)` of solution obtained by dissolving 0.1 g potassium ferricyanide (mol wt = 329) in 100 g water. If `K_(f)` for water is `1.86 K kg mol^(-1)`A. `-2.3xx10^(-2)`B. `-5.7xx10^(-2)`C. `-5.7xx10^(-3)`D. `-1.2xx10^(-2)`

Answer» Correct Answer - A
`DeltaT_(f)=4xx(0.1)/(329)xx(1000)/(100)xx1.86=2.26xx10^(-2)`
`K_(3)[Fe(CN)_(6)]:.i=4`


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