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What will be the difference in temperatures between two sides of a metallic plate 10 mm thick if heat is conducted at the rate of 5 xx 10^5cal/min/m^2 . K for metal is 0.7 cal s^(-1)cm^(-1) ""^@C^(-1) . |
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Answer» SOLUTION :`Delta x = 10 MM = 1 cm` `K = 0.7 CAL s^(-1) cm^(-1) K^(-1)` ` Q = 5 xx 10^5 cal , A = 1m^2 = 10^4cm^2` t = 1 min = 60 s ` Q = (KA(T_1 - T_2)t)/(Delta x)` ` rArr T_1 - T_2 = (Q Delta x)/(KA t) = (5 xx 10^5 xx 1)/(0.7 xx 10^4 xx 60)` ` T_1 - T_2 = 1.19^@C` |
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