What will be the density of lead under a pressure of 20,000 N cm-2. De

1.	What will be the density of lead under a pressure of 20,000 N cm-2. Density of lead is 11.4 g cm-3 and the bulk modulus of lead is 0.80 x 1010 Nm-2
Answer» Bulk modulus, K = Δp.V/ΔV K = 0.80 x 10¹⁰ Nm^-2 = {0.80 x 10¹⁰}/{10⁴} Ncm^-2 Δp = 20,000 N cm^-2 ⇒ ΔV/V = Δp/B = {20000 x 10⁴}/{0.80 x 10¹⁰} = 1/40 or, ΔV = V/40 Now, volume V' = V - V/40 = 39V/40 Since the mass of lead will remain the same, we have Vρ = V'ρ' New density, ρ' = {V x 11.4 x 40}/{39V} = 11.7 g cm^-3

What will be the density of lead under a pressure of 20,000 N cm-2. Density of lead is 11.4 g cm-3 and the bulk modulus of lead is 0.80 x 1010 Nm-2

Answer»

Bulk modulus, K = Δp.V/ΔV

K = 0.80 x 10¹⁰ Nm^-2 = {0.80 x 10¹⁰}/{10⁴} Ncm^-2

Δp = 20,000 N cm^-2

⇒ ΔV/V = Δp/B = {20000 x 10⁴}/{0.80 x 10¹⁰} = 1/40

or, ΔV = V/40

Now, volume V' = V - V/40 = 39V/40

Since the mass of lead will remain the same, we have Vρ = V'ρ'

New density,

ρ' = {V x 11.4 x 40}/{39V} = 11.7 g cm^-3