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What will be the area of a 2 metre wide boundary around a reactangular field ? I.The breadth of the field is one-fourth of its permeter. Area of the field is 144 sq. metre. II. The ratio of the length and breadth is respectively `3:2.` III Area of the field is 216 sq. metre.A. I, II and IIIB. only I or II and IIIC. I and IID. Anyone of the three statements |
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Answer» Correct Answer - B From statement I, If Length = x metre and breadth = y metre, then `y=(1xx2)/(4)(x+y)" "implies2y=x+yimpliesy=x` `thereforex^(2)=144" "impliesx=sqrt(144)=12` metre area of field `=(16)^(2)-(12)^(2)=256-144=112` sq. metre From statements II and III, Length = 3x metre Breadth = 2x metre `therefore3x xx2x=216` `impliesx^(2)=(216)/(3xx2)=36` `impliesx=6` `therefore` Length = 18 metre, Breadth = 12 metre area of the field with boundary `=(18+2xx2)(12+2xx2)` `=22xx16=352` sq. metre `therefore` Area of boundary `=352-216=136` sq. m. |
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