1.

What will be the angle of deviation through a prism and 60°, when angles of incidence and emergence are 45° each?

Answer»

Given: Angle of prism, A = 60° 

Angle of incidence, i = 45° 

Angle of emergence e = 45° 

To find: Angle of deviation = D 

We know 

A + D = i + e 

So, D = i + e – A 

D = 45° + 45° – 60° = 30° 

Hence angle of deviation is 30°



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