Saved Bookmarks
| 1. |
What will be normality of 1 M KMnO4 solution ? [Guj. Board-2007)(a) 0.1 N(b) 2N(c) 100N(d) 5 N |
|
Answer» 4Mn2++16F−→4MnF4−+4e−→ CHANGE of 4e− Molarity of KMnO4=0.025m Normality = Molarity× n-factor =0.025×4 =0.1N |
|