1.

What will be current through the 200 Omega resistor in the given circuit a long time after the switch 'K' is made on?

Answer»

zero
100 mA
10 mA
1 mA

Solution :As key is ON for long, the circuit is in steady STATE. Hence, resistance of each CAPACITOR is infinite. Thus current through resistances 200 `OMEGA ` and 400 `Omega ` is same. Now, equivalent resistance,
` R_(eq)= 200Omega+ 400omega= 600 omega `
`therefore`currentthrough`200Omega `

resistancewill be
` I_("steady ")+(6V )/( 600 Omega ) =10 mA `


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