Saved Bookmarks
| 1. |
What weight of sodium cloride decomposed by `4.9 g` of sulphuric acid, if 6 g of sodium hydrogen sulphide `(NaHSO_(4))` and `1.825 g` of hydrogen chloride are produced in the same reaction ? |
|
Answer» The chemical equation for the reaction is : `NaCl+H_(2)SO_(4)rarrNaHSO_(4)+HCl` Weight of the reaction = Weight of NaCl + Weight of `H_(2)SO_(4)` `= x = 4.9 g` (Here `x` is the weight of `NaCl`) Weight of products = Weight of `NaHSO_(4)+` Weight of `HCl` `= 6.0 g+ 1.825 g = 7.825 g` Now, according to law of conservation of mass Weight of reaction = Weight of products `x=4.9=7.825,x=7.825-4.9=2.925g` `:.` Weight of `NaCl` decomposed `= 2.925 g`. |
|