Saved Bookmarks
| 1. |
What volume of oxygen (NTP) will be required to react with 1 g of Ca? |
|
Answer» Solution :As Ca combines with `O_(2)` to give CaO , from the FORMULA of CaO, We have moles of Ca = moles of O (atoms) `(wt. of Ca)/( at . wt.) = ("vol . of O atoms at NTP")/("vol . OCCUPIED by 1 moleof O ATOMSOF NTP")` `(1)/(40)= (vol . of O)/( 11.2)` ` :. ` vol of O = `(11.2)/( 40) = 0 . 28` litre. |
|