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| 1. |
What volume of CCl_4 (d = 1.6 g/cc) contains 6.02 × 10^{25} CCl_4 molecules (Cl = 35.5)? |
| Answer» What volume of CCl_4 (d = 1.6 g/cc) contains 6.02 × 10^{25} CCl_4 molecules (Cl = 35.5)? | |