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What volume of CCl_4 (d = 1.6 g/cc) contains 6.02 × 10^{25} CCl_4 molecules (Cl = 35.5)?

Answer» What volume of CCl_4 (d = 1.6 g/cc) contains 6.02 × 10^{25} CCl_4 molecules (Cl = 35.5)?


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