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What volume of 6M HCl and 2M HCl should be mixed to get two litres of 3M HCl? |
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Answer» the volume of 6M HCl required to prepare 1 L of 3M HCl = x L Volume of 2M HCl required = 1 - x L Apply molarity EQUATION M1V1 + M2V2 = M3V3 6 � (x) + 2 ( 1-x) = 3 x 1 6X + 2 - 2X = 3 4x +2 = 3 4x = 3 - 2 4x = 1 x = 1/4 = 0.25 L so, volume of 6M HCl required = 0.25 L volume of 2M HCl required = 1 - 0.25 = 0.75 L |
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