What transition of `Li^(+2)` spectrum will have same wavelength as that of second line of Balmer series in `He^(+)` spectrum ?

What transition of `Li^(+2)` spectrum will have same wavelength as tha

1.	What transition of `Li^(+2)` spectrum will have same wavelength as that of second line of Balmer series in `He^(+)` spectrum ?
Answer» `(1)/(lambda_(He^(+))) = (1)/(lambda_(Li^(+)))` `RZ^(2) [(1)/(n_(1)^(2))-(1)/(n_(2)^(2))] = RZ^(2) [(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]` `2^(2) [(1)/(2^(2))-(1)/(4^(2))] = 3^(2) [(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]` `4[(1)/(4)-(1)/(16)] = 9 [(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]` `(4)/(9) xx (3)/(16) = [(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]` `:. (1)/(n_(1)^(2)) -(1)/(n_(2)^(2)) = (1)/(12) n_(1) = 3, n_(2) = 6` `(3 rarr 6)` will have same wavelength as that of second line of Balmer series in `He^(+)` spectrum.

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What transition of `Li^(+2)` spectrum will have same wavelength as that of second line of Balmer series in `He^(+)` spectrum ?

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