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What should be the velocity of a listener so that the apparent frequency of the sound coming from a stationary source to him will be twice the actual frequency ? Velocity of sound in air = v . |
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Answer» Solution :APPARENT frequency, n. = (V = u_(o))/( v - u_(s)) xx n ` In this case apparent frequency higher , the LISTENER is approaching the source, i.e., velocity of the listener ` u_(o)` is positive . Again, ` n. = 2n ` . ` therefore 2n = (v+ u_(o))/(v) xx n " or " , 2V+ v + u_(o) " or " , u_(o) = v ` i.e., the listener is approaching the stationary source with the velocity of sound . |
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