1.

What should be the angle of incidence for a ray of light which suffers a minimum deviation of 36° through an equilateral prism?[Hint: A = 60°, i = (A + δmin)/2]

Answer»

Given,

Angle of prism, A = 60°

Angle of minimum deviation, = 36°

Angle of incidence, i =?

As δmin = 2i – A

36° = 2i – 60

i = 48°



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