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What's the displacement of a body which is thrown vertically up with a velocity of 30 m/s after 6 seconds |
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Answer» Answer: 4.9m/s Explanation: Velocity HALF SECOND before maximum height = Velocity half second after maximum height (Return journey) For DOWNWARD journey : Initial velocity u=0 m/s We have g=9.8 m/s2 Time t=21 s Thus velocity after half second v=u+gt v=0+9.8×21=4.9m/s Hope this will HELP youIf this is helps you MARK me as Brainlist |
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