1.

what possible values of resultant resistance are possible by the combining two resistors R1=4 ohm and R2=12ohm.

Answer»

Answer:

16 ohm and 3 ohm

Explanation:

According to the GIVEN question,

R1 = 4 ohm and R2 = 12 ohm

And we are ASKED to find possible equivalent RESISTANCE.

We know, there are only TWO combination of resistors, i.e, series and parallel combination.

For series combination,

  • R = R1+R2

Where R is equivalent resistance of series combination of R1 and R2.

Putting the values we get,

  • R = 4+12 = 16 ohm

Again, for parallel combination

  • 1/R' = 1/R1 + 1/R2

Where R' is equivalent resistance of parallel combination of R1 and R2.

Putting the values we get,

  • 1/R' = 1/4 + 1/12

  • R' = 4×12/16

  • R' = 12/4

  • R' = 3 ohm

Thus the two possible equivalent resistance are 3 ohm and 16 ohm.


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