What points on the x-axis is equidistance from (7,6) and (-3,4)?

1.	What points on the x-axis is equidistance from (7,6) and (-3,4)?
Answer» <P>Answer: (3,0) Step-by-step explanation: If the point is on x axis, y- coordinate is zero. Let the point be P(x,0) A = (7,6) B = (-3,4) AP = BP AP² = BP² (x-7)² + (0-6)² = (x+3)² + (0-4)² Solving, we get x²+49-14x+36 = x²+9+6x+16 49+36-9-16 = 6x+14x 60 = 20x x= 3 Therefore point is (3,0) ****** Hope it HELPS. Please MARK as BRAINLIEST. :)

Answer»

<P>Answer:

(3,0)

Step-by-step explanation:

If the point is on x axis, y- coordinate is zero.

Let the point be P(x,0)

A = (7,6)

B = (-3,4)

AP = BP

AP² = BP²

(x-7)² + (0-6)² = (x+3)² + (0-4)²

Solving, we get

x²+49-14x+36 = x²+9+6x+16

49+36-9-16 = 6x+14x

60 = 20x

x= 3

Therefore point is (3,0)

******

Hope it HELPS. Please MARK as BRAINLIEST. :)

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What points on the x-axis is equidistance from (7,6) and (-3,4)?​

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What points on the x-axis is equidistance from (7,6) and (-3,4)?