What number must be added to each term of the ratio 9: 16 to make the

1.	What number must be added to each term of the ratio 9: 16 to make the ratio 2: 3?
Answer» Let the number be x, Then the two term becomes, = (9 + x): (16 + x) = 2: 3 = (9 + x) / (16 + x) = (2/3) By cross multiplication, = 3 × (9 + x) = 2 × (16 + x) = 27 + 3x = 32 + 2x Transposing 27 to RHS and 2x to LHS = 3x – 2x = 32 – 27 = x = 5 Hence, the number be added to each of the ratio 9:16 to make the ratio 2: 3 is 5

What number must be added to each term of the ratio 9: 16 to make the ratio 2: 3?

Answer»

Let the number be x,

Then the two term becomes,

= (9 + x): (16 + x) = 2: 3

= (9 + x) / (16 + x) = (2/3)

By cross multiplication,

= 3 × (9 + x) = 2 × (16 + x)

= 27 + 3x = 32 + 2x

Transposing 27 to RHS and 2x to LHS

= 3x – 2x = 32 – 27

= x = 5

Hence, the number be added to each of the ratio 9:16 to make the ratio 2: 3 is 5