What number am I?Clue 1 When you divide me by 5, the remainder is d.Cl

1.	What number am I?Clue 1 When you divide me by 5, the remainder is d.Clue 2 I have two digits. Both digits are odd.Clue 3 The sum of my digits is 10.42.
Answer» answer is 191)If we divide 19 by 5,the remainder is 42)two digits 1and9 both are odd3)sum of two digits 1+9=10 If you didn't understand ask again will clearly explain The possible combinations of digits are (1, 9), (3, 7), (5, 5), (7, 3), (9, 1) Out of these only 19 gives remainder when divided by 4.Therefore 19 is the required number.

What number am I?Clue 1 When you divide me by 5, the remainder is d.Clue 2 I have two digits. Both digits are odd.Clue 3 The sum of my digits is 10.42.

Answer»

answer is 191)If we divide 19 by 5,the remainder is 42)two digits 1and9 both are odd3)sum of two digits 1+9=10

If you didn't understand ask again will clearly explain

The possible combinations of digits are (1, 9), (3, 7), (5, 5), (7, 3), (9, 1)

Out of these only 19 gives remainder when divided by 4.Therefore 19 is the required number.