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What number added to 1 gives its own square? |
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Answer» Let the number be x x + 1 = x2 x2 - x - 1 = 0 \(x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{1\pm \sqrt{1+4}}{2}\) \(=\frac{1\pm \sqrt{5}}{2}\) Numbers \(\frac{1+\sqrt{5}}{2},\frac{1-\sqrt{5}}{2}.\) |
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