What must be subtracted from 3a2−6ab−eb2−1 to get 4a2−7ab−4b – InterviewSolution

1.	What must be subtracted from 3a2−6ab−eb2−1 to get 4a2−7ab−4b2+1?
Answer» What must be subtracted from $3 a^{2} - 6 a b - e b^{2} - 1$ to get $4 a^{2} - 7 a b - 4 b^{2} + 1$ ?

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