1.

What must be substract from x^3+4x^2+6x-6 to obtain x^3+5x^2+9x-7 ?​

Answer»

Answer:

LET y must be subtracted from x^3+4x^2+6x-6 to obtain x^3+6x^2+9x-7

then ,

x^3+4x^2+6x-6 - y = x^3+6x^2+9x-7

-y = x^3+6x^2+9x-7 - (x^3+4x^2+6x-6)

-y = x^3+6x^2+9x-7-x^3-4x^2-6x+6

-y = x^3-x^3+6x^2-4x^2+9x-6x-7+6

-y = 2x^2+3x-1

-y = -(-2x^2-3x+1)

y = -2x^2-3x+1

therefore -2x^2-3x+1 must be subtracted from x^3+4x^2+6x-6 to obtain x^3+5x^2+9x-7

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