What must be added to the polynomial x³-6x²+11x-87 to obtain a polyn

1.	What must be added to the polynomial x³-6x²+11x-87 to obtain a polynomial exactly divisible by (x-3)
Answer» ANSWER: first we have to factor it Step-by-step EXPLANATION: x-3)x³-6x²+11x-87(x²+3x+20 x³-3x² =. × 3x²+11x 3x²-9x =. × 20x-87 20x-60 =. × 27 to get the polynomial wo should SUBSTRACT 27 in the equation

What must be added to the polynomial x³-6x²+11x-87 to obtain a polynomial exactly divisible by (x-3)

Answer»

ANSWER:

first we have to factor it

Step-by-step EXPLANATION:

x-3)x³-6x²+11x-87(x²+3x+20

x³-3x²

=. × 3x²+11x

3x²-9x

=. × 20x-87

20x-60

=. × 27

to get the polynomial wo should SUBSTRACT 27 in the equation

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What must be added to the polynomial x³-6x²+11x-87 to obtain a polynomial exactly divisible by (x-3)​

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What must be added to the polynomial x³-6x²+11x-87 to obtain a polynomial exactly divisible by (x-3)