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What mass of sodium chloride would be decomposed by 9.8 g of sulphuric acid. If 12 g of sodium bisulphate and 2.75 g of hydrogen chloride were produced in a reaction assuming aht the law of conservation of mass is true? |
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Answer» Solution :`NACL+H_(2)SO_(4)=NaHSO_(4)+HCl` ACCORDING to law of conservation of mass. TOTAL masses of reactants =Total masses of products Let the mass of NaCl decomposed be xg, so `x+9.8=12.0+2.75=14.75 x=4.95g |
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