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What mass of sodium chloride (NaCl) forms when 7.5 g of sodium carbonate (Na2CO3) reacts with a dilute solution of hydrochloric acid (HCl)?es001-1.jpgFinally, solve (remember significant figures): |
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Answer» Answer: Given: Mass of sodium carbonate = 7.5 G To find: Mass of sodium chloride (NaCl) = ? Calculation: The chemical equation involved in the given reaction is as follows: In the above reaction, 1 mole of sodium carbonate gives 2 moles of sodium chloride. To find the grams and volume, the molecular weight of reactant as well as product must be calculated. Accordingly, the molecular mass is as follows: = 2 (23) + 1 (12) + 3 (16) = 46 + 12 + 48 = 106 g/mol = 2 (23 + 35.5) = 2 (58.5) = 117 g/mol Weight of sodium chloride formed: As per the given chemical equation, 160 g of gives = 117 g of NaCl (1) 7.5 g of gives = 'X' g of NaCl (2) When the equation 1 and 2 are cross multiplied it gives: X × 106 = 117 × 7.5 X = X = X = 8.28 Conclusion: Thus it is inferred that 7.5 g of sodium carbonate () reacts with a dilute solution of HYDROCHLORIC ACID (HCl), it yields 8.28 g of NaCl. Step-by-step explanation: |
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