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What mass of sodium chloride (NaCl) forms when 7.5 g of sodium carbonate (Na2CO3) reacts with a dilute solution of hydrochloric acid (HCl)? es001-1.jpg Finally, solve (remember significant figures): |
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Answer» ong>Answer: Given:
Mass of sodium carbonate = 7.5 g
To FIND:
Mass of sodium chloride (NaCl) = ?
Calculation:
The chemical equation involved in the given reaction is as follows:
In the above reaction, 1 mole of sodium carbonate gives 2 moles of sodium chloride. To find the grams and volume, the MOLECULAR weight of reactant as well as product must be calculated. Accordingly, the molecular mass is as follows:
= 2 (Na) + 1 (C) + 3(O)
= 2 (23) + 1 (12) + 3 (16)
= 46 + 12 + 48
= 106 g/mol
= 2 (23 + 35.5)
= 2 (58.5)
= 117 g/mol
Weight of sodium chloride FORMED:
As per the given chemical equation,
160 g of gives = 117 g of NaCl (1)
7.5 g of gives = 'X' g of NaCl (2)
When the equation 1 and 2 are cross multiplied it gives:
X × 106 = 117 × 7.5
X =
X =
X = 8.28
Conclusion:
Thus it is INFERRED that 7.5 g of sodium carbonate () reacts with a dilute solution of hydrochloric acid (HCL), it yields 8.28 g of NaCl.
Step-by-step explanation: |
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