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What mass of CaO will be required to remove the hardness of 1000 litre of water containing 1.62 g of calcium bicarbonate per litre? |
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Answer» The following balanced equation represents the reaction occurring during removal temporary hardness of water due to the presence of Ca(HCO3)2 in water CaO + Ca(HCO3)2 ->2CaCO3+H2O 40+16. 40+(1+12+3×16)×2 =56. = 162 Given 1L water contains 1.62g bicarbonate So 1000 L Water contains 1620g bicarbonate By the above balanced equation we know 162 g bicarbonate requires 56 g CaO Hence 1620 g bicarbonate will require 560g CaO |
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