1.

What mass of CaO will be required to remove the hardness of 1000 litre of water containing 1.62 g of calcium bicarbonate per litre?

Answer» The following balanced equation represents the reaction occurring during removal temporary hardness of water due to the presence of Ca(HCO3)2 in water

CaO   +  Ca(HCO3)2 ->2CaCO3+H2O

40+16.   40+(1+12+3×16)×2

=56.        = 162

Given 1L water contains 1.62g bicarbonate

So 1000 L Water contains 1620g bicarbonate

By the above balanced equation we know

162 g bicarbonate requires 56 g CaO

Hence 1620 g bicarbonate will require 560g CaO


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