What mass of ca will contain the same number of atoms as are present i

1.	What mass of ca will contain the same number of atoms as are present in 3.2 g of s?
Answer» Gmm of sulphur=32gram 1 mole sulphur=6.02310^23 atoms(in 32 GRAM sulphur) 3.2 gram sulphur WOULD contain= 6.02310^23 3.2/32= 6.02310^22 gmm of calcium=40G 1mole of calcium= (40g) mass of 6.02310^22 calcium = 406.02310^22/6.02310^23= 4 GRAMS

Discussion