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What is wavelength of the slectron if the kinetic energy is 0.3yj |
Answer» Answer:WAVELENGTH (Lambda) = h/ROOT ( 2 m K. E.)Lambda = 6.626 × 10^(-34) / root ( 2 × 9. 1 × 10^(-31)× 0.3 × 1000) Lambda = 6. 26 × 10^ ( - 34) / root (5460 × 10^(-31)) Lambda = 6.626 × 10^(-34)/ 233.4 Lambda = 0.0283 × 10^(-34) m. |
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