1.

What is the work done in taking an object of mass 1kg from the surface of the earth to a height equal to the radius of the earth ? (G = 6.67 xx 10^(-11) Nm^(2)//Kg^(2), Radius of the earth = 6400 km, Mass of the earth = 6 xx 10^(24) kg.)

Answer»

SOLUTION :The work DONE in taking an OBJECT to a height
`= (GMm)/(R(R+h)) , ""` Here hR
`= (6.67 xx 10^(-11) xx 6 xx 10^(24) xx 1)/(2 xx 6.4 xx 10^(6)) = 3.127 xx 10^(7)J`.


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