1.

What is the work done in increasing the angular frequency of a circular ring of mass 2 kg and radius 25 cm from 10 rpm to 20 rpm about is axis ?

Answer»

Solution :WORK done = Increase in ROTATIONAL kinetic ENERGY `=(1)/(2)I(omega_(f)^(2)-omega_(i)^(2))=(1)/(2)MR^(2)(omega_(f)^(2)-omega_(i)^(2))`
`= (1)/(2)xx2xx(0.25)^(2)(((2PI)/(3))^(2)-((pi)/(3))^(2))=0.2058 J`


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