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What is the work done in increasing the angular frequency of a circular ring of mass 2 kg and radius 25 cm from 10 rpm to 20 rpm about is axis ? |
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Answer» Solution :WORK done = Increase in ROTATIONAL kinetic ENERGY `=(1)/(2)I(omega_(f)^(2)-omega_(i)^(2))=(1)/(2)MR^(2)(omega_(f)^(2)-omega_(i)^(2))` `= (1)/(2)xx2xx(0.25)^(2)(((2PI)/(3))^(2)-((pi)/(3))^(2))=0.2058 J` |
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