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What is the weight of oxygen required for thecomplete combustion of 2.8 kg of ethylene?3.[AIPMT 1989](A) 2.8 kg(C) 9.6 kg(B) 6.4 kg(D) 96 kg |
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Answer» The chemical equation for the said reaction is, C2H4+12×2+4=283O296→2CO2+2H2O the gram molar weight of ethylene is= 12*2+1*4 g =28gthe gram molar weight of oxygen = 3*32 g =96 g∵The weight of oxygen required for complete combustion of 28 g ethylene =96 gaccording to question, ∴ Weight of oxygen required for combustion of 2.8 kg ethylene =96×2.8×100028×1000kg =9.6kgThat is the answer. |
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