What is the volume of S.T.P of 2.8 g of nitrogen gas . [N=14]

1.	What is the volume of S.T.P of 2.8 g of nitrogen gas . [N=14]
Answer» HERE IS YOUR ANSWER One mole of nitrogen GAS occupies 22.4 L of volume. So let us first find out the number of MOLES....... So N2 = 214 = 28 g/mol. So 2.8 g of N2 CONTAINS (2.8 / 28 )moles = 0.1 mole. So the gas will occupy a volume of 0.1 22.4 = 2.24 L of volume. THANK YOU

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