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| 1. |
What is the value of tan 15° |
| Answer» We can find its value as follows:-tan15°= tan(45°-30°) = {tex}{tan 45° - tan30°\\over 1+tan45°tan30°}{/tex} = {tex}{1- {1\\over {\\sqrt 3}}}\\over1+1×{1\\over {\\sqrt 3}}{/tex} = {tex}{{{\\sqrt 3}-1}\\over {\\sqrt 3}}\\over {{{\\sqrt 3}+1}\\over {\\sqrt 3}}{/tex} = {tex}{\\sqrt 3}-1\\over {\\sqrt 3}+1{/tex} | |