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What is the value of k for which the equation x^2 -2kx+7k-12 has equal real roots? |
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Answer» ANSWER:k=3,4 Step-by-step EXPLANATION: B^2=4ac 4k^2=4(1)(7k-12) K^2=7k-12 K^2-7k+12=0 K^2-4k-3k+12=0 K(k-4)-3(k-4)=0 (K-4)(k-3)=0 K=3,4 Hope it HELPS... |
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