1.

What is the value of ?:- 2cos²thita (1 +tan² thita)​

Answer» ONG>Answer:

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Step-by-step EXPLANATION:

cos^2A = 1 / Sec^2A

or ( 1 + tan^2A = Sec^2A )

: 2 × 1/Sec^2A ( sec^2A )

= 2 ( 1 / sec^2A × sec^2 = 1 )



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