What is the unit of y^+?(a) y^+ is dimensionless(b) m(c) m^2(d) 1⁄mI have been asked this question in an interview for internship.My doubt is from Turbulence Modelling in chapter Turbulence Modelling of Computational Fluid Dynamics

What is the unit of y^+?(a) y^+ is dimensionless(b) m(c) m^2(d) 1⁄mI

1.	What is the unit of y^+?(a) y^+ is dimensionless(b) m(c) m^2(d) 1⁄mI have been asked this question in an interview for internship.My doubt is from Turbulence Modelling in chapter Turbulence Modelling of Computational Fluid Dynamics
Answer» The CORRECT option is (a) y^+ is dimensionless The explanation is: y^+ is dimensionless length. It does not have any dimensions. This can be again proved from the equation y^+ (unitless and dimensionless)= \(y(m)u_t(\FRAC{m}{s})⁄ν(\frac{m^2}{s})\).

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