1.

What is the torque of the force f=2i-5j+4k m acting at the point r=3i+3j+3k m about the origin​

Answer»

r is 0 Nm.

Explanation:

we know that torque=F×r

where F×r MEANS Fr sin theta.

we have F=2i+5j+4k

and. r=3i+3j+3k

theta =0. ( becouse in the question they GAVE US theta is about the origin)

substitute the values in the formula

torque=(2i+5j+4k)(3i+3j+3k)0 Nm.

therefore torque becomes 0 Nm.

The units for torque are Nm.

Additional information: torque is ALSO known as moment of force.

Hope this will HELP you.



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