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What is the torque of the force f=2i-5j+4k m acting at the point r=3i+3j+3k m about the origin |
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Answer» r is 0 Nm. Explanation: we know that torque=F×r where F×r MEANS Fr sin theta. we have F=2i+5j+4k and. r=3i+3j+3k theta =0. ( becouse in the question they GAVE US theta is about the origin) substitute the values in the formula torque=(2i+5j+4k)(3i+3j+3k)0 Nm. therefore torque becomes 0 Nm. The units for torque are Nm. Additional information: torque is ALSO known as moment of force. Hope this will HELP you. |
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