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What is the time period of ratation of the earth around its axis so that the objects at the equator becomes weightless? (g=9.8 m//s^2 , Radius of earth =6400 km) |
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Answer» Solution :g at the equator is `g_0=g-g_0=g-Romega^2` If bodies are to become WEIGHTLESS at the equator, `g_0=0`. `0=g-Romega^2 rArr Romega^2 =g` `omega=sqrt(g/R)` Time PERIOD of roration, `T=(2PI)/omega=2pisqrt(R/g)` `R=6400xx10^3` m , `g=9.8 m//s^2` `T=2pisqrt((6.4xx10^6)/9.8)`=5078 s =84 MINUTE 38 s. |
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