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What is the sum of the even integers from 100 to 1000

Answer»

Solving this question with AP :

Given,
a = 100 \\ d = 1 \\ l = 1000 \\n = 900 \\  =  \frac{n}{2} (a + l) \\  = \frac{900}{2}(100 + 1000) \\  = 450 \times 1100 \\  = 495000
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