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What is the specific kinetic energy of a fluid flowing at rate 0.1 m^3/s and 1 m diameter pipe?(a) 0.008 J/Kg(b) 0.016 J/Kg(c) 0.028 J/Kg(d) 0.064 J/Kg |
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Answer» Right answer is (a) 0.008 J/Kg The best explanation: v = 0.1/∏(0.5)^2, => specific KE = v^2/2 = 0.008 J/Kg. |
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