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What is the specific heat capacity of iron if it takes 125 J of heat to raise 111 grams by 2.5 degrees Celsius? |
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Answer» C = 450.45 J /Kg °CExplanation: We have a formula, Q = mC∆T where we take Q in joules, m in Kgs and ∆T in °C. Now first of all, we will need to change m in kgs. We know that, 1 kg = 1000G 1kg 111 g × ---------- = 0.111 kg 1000g Now, we will SET the formula, Q = mc∆T ------ --------- (Dividing m∆T on both sides) m∆T m∆T ==> Q C = -------- m∆T now, PUTTING the values, 125 J C = ---------------------------- 0.111 Kg × 2.5 °C C = 450.45 J /Kg °C which is the required answer. |
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