1.

What is the smallest number that when divided by 35, 56 and 91 leaves remainder of 7 in each case.​

Answer»

Step-by-step explanation:

since the question states for smallest no we have to FIND LCM

1st Subtract 7 from all 3 numbers

2nd You will get 28, 49, 84

3rd Hence find the LCM for all 3 numbers

4th you will get 252

That's the RIGHT answer hope it is HELPFUL mark mine as the brainliest if u UNDERSTAND it.



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