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What is the smallest number that when divided by 35, 56 and 91 leaves remainder of 7 in each case. |
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Answer» Step-by-step explanation: since the question states for smallest no we have to FIND LCM 1st Subtract 7 from all 3 numbers 2nd You will get 28, 49, 84 3rd Hence find the LCM for all 3 numbers 4th you will get 252 That's the RIGHT answer hope it is HELPFUL mark mine as the brainliest if u UNDERSTAND it. |
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