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What is the slope of the plot of ln (t0.5) and ln (CAo)? (Where n is the reaction order)(a) 1-n(b) 2-n(c) n(d) (frac{n}{2} ) |
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Answer» The correct option is (a) 1-n The explanation is: The plot is a straight line of slope (1-n). The equation representing the relationship is ln (t0.5) = ln((frac{(2^{n-1}-1)}{(n-1)k})) + (1 – n) ln (CAo). |
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