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What is the reversible work done if 4 m^3 of an ideal gas is compressed adiabatically pV1.5 = K from 2 Pa to 16 Pa?(a) 4 J(b) 16 J(c) 24 J(d) 56 J

Answer» Correct option is (b) 16 J

For explanation: V2 = (2*4^1.5/16)^1/1.5 = 1 m^3, => W = –4∫^1pdv = –4∫^1 (16/v^1.5) dv = 16 J.


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