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What is the reversible work done if 4 m^3 of an ideal gas is compressed adiabatically pV2.5 = K from 1 Pa to 32 Pa?(a) 18.6 J(b) 20.4 J(c) 24.6 J(d) 26.2 J |
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Answer» Correct answer is (a) 18.6 J For explanation I would say: V2 = (1*4^2.5/32)^1/2.5 = 1 m^3, => W = –4∫^1pdv = –4∫^1 (32/v^2.5) dv = 18.6 J. |
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