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What is the remainder when 10x^159-5 is divided by (x-1)? show solution pls |
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Answer» The polynomial REMAINDER theorem says that when f(x) is DIVIDED by (x−a), the remainder is given by f(a). Here, f(x)=x5+1 and it is divided by (x−2) ∴a=2 ∴Remainder=f(2)=25+1=33 |
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