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What is the refractive index of E-layer when the electromgnetic wave frequency is 50 MHz and the number density of electrons is `5xx10^(5)` electrons is `5xx10^(5)` electrons`//cm^(3)` ?A. 0-992B. 1-015C. 43481D. 1-000

Answer» Hre, `N=5xx10^(5)` electrons//cm^(3)`
`=5xx10^(5)xx10^(6)` electorns`//m^(3)`
`=v50 MHz=50xx10^(6)`Hz
`mu=sqrt(1-(81.45N)/v^(2))=sqrt(1-(81.45xx5xx10^(5)xx10^(6))/((50xx10^(6))^(2)))`
`sqrt(1-(81.45xx10^(-3))/(5))`
`=sqrt(1-0.01629)=sqrt(0.98371)=0.992`


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