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what is the ratio of moles of `Mg(OH)_(2)` and `AI(OH)_(3)` present in 1 litre saturated aqueous solution of `Mg(OH)_(2)` and `AI(OH)_(3)` (Given `K_(sp)` of `Mg(OH)_2)=4xx10^(-12)` asnd `K_(sp)` of `AI(OH)_(3)` is `1xx10^(-33)`). Report your answer after multiplying by `10^(-17)` . |
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Answer» Correct Answer - 8 What is the ratio of ……………. `{:(Mg(OH)_(2),,hArr,Mg^(2+)+2OH^(-)),(,x, 2x+3y),(AI(OH)_(3),hArr,AI^(3+)+3OH^(-)),(,y,3y+2x):}` Since `K_(ap)` of `Mg(OH)_(2)gt K_(ap)` of `AI(OH)_(3)` `:. X gtgt y` , `:. 2x+3y~=2x` `4xx10^(-12)= [Mg^(2+)][OH^(-)]^(2)` `=x+(2x)^(2)` `:. x= 10^(-4)` Similary `1xx10^(-33)=[AI^(3+)][OH^(-)]^(3)` `1xx10^(-33)=yxx(2x)^(3)` `:. y = (10^(-21))/(8)` Thus `(x)/(y) = 8xx10^(17)` `:.` Ans. `= 8xx10^(+17) = 8` |
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