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What is the ratio of equivalent resistance of series combination of `n` equal resistance to the equivalent resistance in parallel combination of these `n` resistances ? |
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Answer» Equivalent resistance of series combination of `n` equal resistances (each resistance equal to `r`), i.e., `R_s = nr` Equivalent resistance of parallel combination of `n` equal resistance (each resistance equal to `r`), i.e., `R_p = (r )/(n)` Thus, `(R_s)/(R_p) = (n r)/(r//n) = n^2`. |
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